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相信大家都知道在通常情况下，在Node.js中我们可以通过underscore的extend或者lodash的merge来合并两个对象，但是对于像下面这种复杂的对象，要如何来应对呢？下面来一起学习学习吧。
Node.js合并两个复杂对象
例如我有以下两个object：
代码如下 varobj1 = { "name":"myname", "status": 0, "profile": {"sex":"m","isactive":true}, "strarr":["one","three"], "objarray": [ { "id": 1, "email":"a1@me.com", "isactive":true }, { "id": 2, "email":"a2@me.com", "isactive":false } ] }; varobj2 = { "name":"myname", "status": 1, "newfield": 1, "profile": {"isactive":false,"city":"new York"}, "strarr":["two"], "objarray": [ { "id": 1, "isactive":false }, { "id": 2, "email":"a2modified@me.com" }, { "id": 3, "email":"a3new@me.com", "isactive":true } ] };希望合并之后的结果输出成下面这样：
代码如下 { name:"myname", status: 1, profile: { sex:"m", isactive:false, city:"new York"}, strarr: ["one","three","two"], objarray: [ { id: 1, email:"a1@me.com", isactive:false}, { id: 2, email:"a2modified@me.com", isactive:false}, { id: 3, email:"a3new@me.com", isactive:true} ], newfield: 1 }通过underscore或者lodash现有的方法我们无法实现上述结果，那只能自己写代码来实现了。
代码如下 functionmergeObjs(def, obj) { if(!obj) { returndef; }elseif(!def) { returnobj; } for(variinobj) { // if its an object if(obj[i] !=null&& obj[i].constructor == Object) { def[i] = mergeObjs(def[i], obj[i]); } // if its an array, simple values need to be joined. Object values need to be remerged. elseif(obj[i] !=null&& (obj[i]instanceofArray) && obj[i].length > 0) { // test to see if the first element is an object or not so we know the type of array we"re dealing with. if(obj[i][0].constructor == Object) { varnewobjs = []; // create an index of all the existing object IDs for quick access. There is no way to know how many items will be in the arrays. varobjids = {} for(varx= 0, l= def[i].length ; x < l; x++ ) { objids[def[i][x].id] = x; } // now walk through the objects in the new array // if the ID exists, then merge the objects. // if the ID does not exist, push to the end of the def array for(varx= 0, l= obj[i].length; x < l; x++) { varnewobj = obj[i][x]; if(objids[newobj.id] !== undefined) { def[i][x] = mergeObjs(def[i][x],newobj); } else{ newobjs.push(newobj); } } for(varx= 0, l = newobjs.length; x例如有以下两个对象：
代码如下 vardata1 = { "_id":"577327c544bd90be508b46cc", "channelId_info": [ { "channelId_key":"0", "secondLevel_group": [ { "secondLevel_key":"568cc36c44bd90625a045c60", "sender_group": [ { "sender_key":"577327c544bd90be508b46cd", "sender_sum": 40.0 } ], "senders_sum": 40.0 } ], "channelId_sum": 40.0 } ], "car_sum": 40.0 }; vardata2 = { "_id":"577327c544bd90be508b46cc", "channelId_info": [ { "channelId_key":"0", "secondLevel_group": [ { "secondLevel_key":"568cc36c44bd90625a045c60", "sender_group": [ { "sender_key":"577327c544bd90be508b46cd", "sender_sum": 20.0 }, { "sender_key":"5710bcc7e66620fd4bc0914f", "sender_sum": 5.0 } ], "senders_sum": 25.0 }, { "secondLevel_key":"55fbeb4744bd9090708b4567", "sender_group": [ { "sender_key":"5670f993a2f5dbf12e73b763", "sender_sum": 10.0 } ], "senders_sum": 10.0 } ], "channelId_sum": 35.0 }, { "channelId_key":"1", "secondLevel_group": [ { "secondLevel_key":"568cc36c44bd90625a045c60", "sender_group": [ { "sender_key":"577327c544bd90be508b46cd", "sender_sum": 20.0 } ], "senders_sum": 20.0 } ], "channelId_sum": 20.0 } ], "car_sum": 55.0 };合并之后的结果如下：
代码如下 { "_id":"577327c544bd90be508b46cc", "channelId_info": [ { "channelId_key":"0", "secondLevel_group": [ { "secondLevel_key":"568cc36c44bd90625a045c60", "sender_group": [ { "sender_key":"577327c544bd90be508b46cd", "sender_sum": 60 }, { "sender_key":"5710bcc7e66620fd4bc0914f", "sender_sum": 5 } ], "senders_sum": 65 }, { "secondLevel_key":"55fbeb4744bd9090708b4567", "sender_group": [ { "sender_key":"5670f993a2f5dbf12e73b763", "sender_sum": 10 } ], "senders_sum": 10 } ], "channelId_sum": 75 }, { "channelId_key":"1", "secondLevel_group": [ { "secondLevel_key":"568cc36c44bd90625a045c60", "sender_group": [ { "sender_key":"577327c544bd90be508b46cd", "sender_sum": 20 } ], "senders_sum": 20 } ], "channelId_sum": 20 } ], "car_sum": 95 }