sql server_sql UNION ALL用法详解

更新时间:2017-01-31    来源:php与数据库    手机版     字体:

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union all 这个指令的目的也是要将两个 sql 语句的结果合并在一起。 union all 和 union 不同之处在于 union all 会将每一笔符合条件的资料都列出来,无论资料值有无重复。

union all 的语法如下:

[sql 语句 1]
union all
[sql 语句 2]

我们用和上一页同样的例子来显示出 union all 和 union 的不同。同样假设我们有以下两个表格,

 

1> create table employee(
2>     id          int,
3>     name        nvarchar (10),
4>     salary      int,
5>     start_date  datetime,
6>     city        nvarchar (10),
7>     region      char (1))
8> go
1>
2> insert into employee (id, name,    salary, start_date, city,       region)
3>               values (1,  "jason", 40420,  "02/01/94", "new york", "w")
4> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (2,  "robert",14420,  "01/02/95", "vancouver","n")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (3,  "celia", 24020,  "12/03/96", "toronto",  "w")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (4,  "linda", 40620,  "11/04/97", "new york", "n")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (5,  "david", 80026,  "10/05/98", "vancouver","w")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (6,  "james", 70060,  "09/06/99", "toronto",  "n")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (7,  "alison",90620,  "08/07/00", "new york", "w")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (8,  "chris", 26020,  "07/08/01", "vancouver","n")
3> go

(1 rows affected)
1> insert into employee (id, name,    salary, start_date, city,       region)
2>               values (9,  "mary",  60020,  "06/09/02", "toronto",  "w")
3> go

(1 rows affected)
1>
2> select * from employee
3> go
id          name       salary      start_date              city       region
----------- ---------- ----------- ----------------------- ---------- ------
          1 jason            40420 1994-02-01 00:00:00.000 new york   w
          2 robert           14420 1995-01-02 00:00:00.000 vancouver  n
          3 celia            24020 1996-12-03 00:00:00.000 toronto    w
          4 linda            40620 1997-11-04 00:00:00.000 new york   n
          5 david            80026 1998-10-05 00:00:00.000 vancouver  w
          6 james            70060 1999-09-06 00:00:00.000 toronto    n
          7 alison           90620 2000-08-07 00:00:00.000 new york   w
          8 chris            26020 2001-07-08 00:00:00.000 vancouver  n
          9 mary             60020 2002-06-09 00:00:00.000 toronto    w

(9 rows affected)
1>
2>
3> select id, name from employee where name like "c%"
4> union all
5> select id, name from employee where name like "a%"
6> go
id          name
----------- ----------
          3 celia
          8 chris
          7 alison

(3 rows affected)
1>
2> drop table employee
3> go
1>

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