【www.bbyears.com--面向对象编程】
如何实现如下需求：
$data = array("x" => "xx", "y" => "yy");
echo $data["x"];//输出xx
echo $data->x;//输出xx
方法一：构造一个类，实现ArrayAccess接口和__get,__set魔术方法
class Test implements ArrayAccess {
private $data = null;
public function __construct($data){
$this->data = $data;
}
public function offsetGet($offset){
return ($this->offsetExists($offset) ? $this->data[$offset] : null);
}
public function offsetSet($offset, $value){
$this->data[$offset] = $value;
}
public function offsetExists($offset){
return isset($this->data[$offset]);
}
public function offsetUnset($offset){
if($this->offsetExists($offset)){
unset($this->data[$offset]);
}
}
public function __get($offset){
return ($this->offsetExists($offset) ? $this->data[$offset] : null);
}
public function __set($offset, $value){
$this->data[$offset] = $value;
}
}
测试代码
$data = array("x" => "x", "y" => "y");
$t = new Test($data);
printf("数组方式访问(＼$t["x"])输出：%s
", $t["x"]);
printf("对象方式访问(＼$t->y)输出：%s
", $t->y);
//数组方式赋值，对象方式访问
$t["x1"] = "x1";
printf("数组方式赋值%s
", "＼$t["x1"]="x1"");
printf("对象方式访问(＼$t->x1)输出：%s
", $t->x1);
//对象方式赋值，数组方式访问
$t->y1 = "y1";
printf("对象方式赋值%s
", "＼$t->y1="y1"");
printf("数组方式访问(＼$t["y1"])输出：%s
", $t["y1"]);
方法二
$data = array("x" => "x", "y" => "y");
$t = new ArrayObject($data, ArrayObject::ARRAY_AS_PROPS);
printf("数组方式访问(＼$t["x"])输出：%s
", $t["x"]);
printf("对象方式访问(＼$t->y)输出：%s
", $t->y);
//数组方式赋值，对象方式访问
$t["x1"] = "x1";
printf("数组方式赋值%s
", "＼$t["x1"]="x1"");
printf("对象方式访问(＼$t->x1)输出：%s
", $t->x1);
//对象方式赋值，数组方式访问
$t->y1 = "y1";
printf("对象方式赋值%s
", "＼$t->y1="y1"");
printf("数组方式访问(＼$t["y1"])输出：%s
", $t["y1"]);
测试结果
